function yahoo_status($user){ /************************************* * Copyright ? 2000 Scriptmakers.com * * Feel free to edit, modify and * * redistribute as long as this * * message is kept intact. * *************************************/ $status = @file("http://opi.yahoo.com/online?u=$user"); $status = $status[0]; if($status == "$user is ONLINE"){ return "Online"; }elseif($status == "$user is NOT ONLINE"){ return "Offline"; }else{ return "Unknown"; } } ?>
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